Relation between Floor and Ceiling
From ProofWiki
Contents |
Theorem
Let $x \in \R$ be a real number.
Let $\left \lfloor {x}\right \rfloor$ be the floor of $x$, and $\left \lceil {x}\right \rceil$ be the ceiling of $x$.
Then the following results apply:
Floor of Ceiling is Ceiling
- $\left \lfloor {\left \lceil {x}\right \rceil}\right \rfloor = \left \lceil {x}\right \rceil$
Ceiling of Floor is Floor
- $\left \lceil {\left \lfloor {x}\right \rfloor}\right \rceil = \left \lfloor {x}\right \rfloor$
Floor equals Ceiling iff Integer
- $\left \lfloor {x}\right \rfloor = \begin{cases} \left \lceil {x}\right \rceil & : x \in \Z \\ \left \lceil {x}\right \rceil - 1 & : x \notin \Z \\ \end{cases}$
or equivalently:
- $\left \lceil {x}\right \rceil = \begin{cases} \left \lfloor {x}\right \rfloor & : x \in \Z \\ \left \lfloor {x}\right \rfloor + 1 & : x \notin \Z \\ \end{cases}$
where $\Z$ is the set of integers.
Floor of Negative equals Negative of Ceiling
- $\left \lfloor {-x}\right \rfloor = - \left \lceil {x}\right \rceil$
Ceiling of Negative equals Negative of Floor
- $\left \lceil {-x}\right \rceil = - \left \lfloor {x}\right \rfloor$