Roots of Complex Number/Examples/z^4 + 81 = 0
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Theorem
The roots of the polynomial:
- $z^4 + 81$
are:
- $\set {3 \cis 45 \degrees, 3 \cis 135 \degrees, 3 \cis 225 \degrees, 3 \cis 315 \degrees}$
Proof
From Factorisation of $z^n + 1$:
- $z^4 + 1 = \ds \prod_{k \mathop = 0}^3 \paren {z - \exp \dfrac {\paren {2 k + 1} i \pi} 4}$
Thus:
- $z = \set {\exp \dfrac {\paren {2 k + 1} i \pi} 4}$
\(\text {(k = 0)}: \quad\) | \(\ds z\) | \(=\) | \(\ds \cos \dfrac \pi 4 + i \sin \dfrac \pi 4\) | |||||||||||
\(\text {(k = 1)}: \quad\) | \(\ds z\) | \(=\) | \(\ds \cos \dfrac {3 \pi} 4 + i \sin \dfrac {3 \pi} 4\) | |||||||||||
\(\text {(k = 2)}: \quad\) | \(\ds z\) | \(=\) | \(\ds \cos \dfrac {5 \pi} 4 + i \sin \dfrac {5 \pi} 4\) | |||||||||||
\(\text {(k = 3)}: \quad\) | \(\ds z\) | \(=\) | \(\ds \cos \dfrac {7 \pi} 4 + i \sin \dfrac {7 \pi} 4\) |
$\blacksquare$
Sources
- 1981: Murray R. Spiegel: Theory and Problems of Complex Variables (SI ed.) ... (previous) ... (next): $1$: Complex Numbers: Supplementary Problems: Roots of Complex Numbers: $97 \ \text{(a)}$