Talk:Continuous Involution is Homeomorphism

May I ask what this is used for? Also, it extends a bit (trivially, like the rest):

If $f$ is continuous and $f \circ \dots \circ f = \operatorname{id}$, then $f$ is a homeomorphism. --Dfeuer (talk) 11:44, 14 February 2013 (UTC)

I think it will have use of reference for results on topological algebraic structures (in proving the inversion mapping is a homeomorphism). Other than that, it's simply a result. Trivial, but that does not matter. On the trivial we build the intricate. --Lord_Farin (talk) 11:47, 14 February 2013 (UTC)

I'm not objecting to the triviality; I was just curious. --Dfeuer (talk) 11:54, 14 February 2013 (UTC)