Talk:Product Form of Sum on Completely Multiplicative Function
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It occurs to me that this is only valid if the sum inside the product is absolutely convergent. Needs more work to make it rigorous. --Matt Westwood 05:31, 17 April 2009 (UTC)
... there, I think I've covered it. --Matt Westwood 07:14, 17 April 2009 (UTC)
- Still some convergence issues I think...
- Take it away, then, maestro ... --prime mover 13:49, 2 March 2011 (CST)
- My mistake; forgot that $f$ is multiplicative, so $|f(p)| < 1 \implies$ abs. convergence --Linus44 19:33, 2 March 2011 (CST)
