Talk:Trivial Vector Space iff Zero Dimension

Call to Explain: I suggest to have 'singletons' in place of 'vectors'. --Lord_Farin 15:42, 24 May 2012 (EDT)

Not sure how that would work ... --prime mover 16:57, 24 May 2012 (EDT)

The def'n of lin. indep. set works for singletons, and a singleton is l.i. iff its element isn't $\mathbf 0$. --Lord_Farin 17:01, 24 May 2012 (EDT)

I think that should about do it. --prime mover 17:16, 24 May 2012 (EDT)