Chu-Vandermonde Identity
Contents |
Theorem
Let $r, s \in \R, n \in \Z$.
Then:
- $\displaystyle \sum_k \binom r k \binom s {n-k} = \binom {r+s} n$
where $\displaystyle \binom r k$ is a binomial coefficient.
When $r$ and $s$ are integers, it is more commonly known as Vandermonde's Identity or Vandermonde's Convolution.
Proof
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \sum_n \binom {r + s} n x^n\) | \(=\) | \(\displaystyle \left({1 + x}\right)^{r + s}\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Binomial Theorem | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \left({1 + x}\right)^r \left({1 + x}\right)^s\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Exponent Combination Laws | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \sum_k \binom r k x^k \sum_m \binom s m x^m\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Binomial Theorem | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \sum_k \binom r k x^k \sum_{n-k} \binom s {n - k} x^{n - k}\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \sum_n \left({\sum_k \binom r k \binom s {n-k} }\right) x^n\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) |
As this has to be true for all $x$, we have that:
- $\displaystyle \binom {r+s} n = \sum_k \binom r k \binom s {n-k}$
$\blacksquare$
Alternative Proof
Special case of Gauss's Hypergeometric Theorem:
- $\displaystyle {}_2F_1(a,b;c;1) = \frac{\Gamma(c)\Gamma(c-a-b)}{\Gamma(c-a)\Gamma(c-b)}$
$\displaystyle {}_2F_1$ is the Hypergeometric Series and $\Gamma(n+1)=n!$ is the Gamma function.
One regains the Chu-Vandermonde identity by taking $a = -n$ and applying the identity
- $\displaystyle \binom n k = (-1)^k \binom {k-n-1} k$
liberally.
Comment
This can be interpreted as follows.
The RHS can be thought of as the number of ways to select $n$ people from among $r$ men and $s$ women.
Each term in the LHS is the number of ways to choose $k$ of the men and $n - k$ of the women.
Source of Name
This entry was named for Alexandre-Théophile Vandermonde and Chu Shih-Chieh.
It appeared in Chu Shih-Chieh's The Precious Mirror of the Four Elements in 1303.
It was published by Vandermonde in 1772.
Sources
- Donald E. Knuth: The Art of Computer Programming: Volume 1: Fundamental Algorithms (1968) $\S 1.2.6 \ \text{I} \ (21)$, Exercise $17$
- Murray R. Spiegel: Mathematical Handbook of Formulas and Tables (1968): $3.13$