Closed Ball is Convex Set
Theorem
Let $\struct {X, \norm {\, \cdot \,} }$ be a normed vector space.
Let $\map { {B_r}^-} x$ be a closed ball in $X$ with radius $r \in \R_{>0}$ and center $x \in X$.
Then $\map { {B_r}^-} x$ is convex.
Proof
Let $y \in \map { {B_1}^-} {\mathbf 0}$.
From Norm Axiom $\text N 2$: Positive Homogeneity, it follows that:
- $\norm {r y} = r \norm y$
It follows that:
- $y \in \map { {B_1}^-} {\mathbf 0}$, if and only if $r y \in \map { {B_r}^-} {\mathbf 0}$
As $\norm {r y - \mathbf 0} = \norm {\paren {r y + x} - x}$, it follows that:
- $r y \in \map { {B_r}^-} {\mathbf 0}$
- $r y + x \in \map { {B_r}^-} {\mathbf x}$
It follows that:
- $\map { {B_r}^-} {\mathbf x} = r \map { {B_1}^-} {\mathbf 0} + x$
From Closed Unit Ball is Convex Set, it follows that $\map { {B_1}^-} {\mathbf 0}$ is convex.
From Dilation of Convex Set in Vector Space is Convex, it follows that $r \map { {B_1}^-} {\mathbf 0}$ is convex.
From Translation of Convex Set in Vector Space is Convex, it follows that $r \map { {B_1}^-} {\mathbf 0} + x$ is convex.
$\blacksquare$
Sources
- 1997: Reinhold Meise and Dietmar Vogt: Introduction to Functional Analysis: $\S 5$: Normed Spaces