General Solution of Linear 2nd Order ODE from Homogeneous 2nd Order ODE and Particular Solution
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Theorem
Consider the nonhomogeneous linear second order ODE:
- $(1): \quad \dfrac {\d^2 y} {\d x^2} + \map P x \dfrac {\d y} {\d x} + \map Q x y = \map R x$
Let $\map {y_g} x$ be the general solution of the homogeneous linear second order ODE:
- $(2): \quad \dfrac {\d^2 y} {\d x^2} + \map P x \dfrac {\d y} {\d x} + \map Q x y = 0$
Let $\map {y_p} x$ be a particular solution of $(1)$.
Then $\map {y_g} x + \map {y_p} x$ is the general solution of $(1)$.
Proof
Let $\map {y_g} {x, C_1, C_2}$ be a general solution of $(2)$.
Note that $C_1$ and $C_2$ are the two arbitrary constants that are to be expected of a second order ODE.
Let $\map {y_p} x$ be a certain fixed particular solution of $(1)$.
Let $\map y x$ be an arbitrary particular solution of $(1)$.
Then:
\(\ds \) | \(\) | \(\ds \paren {y - y_p} + \map P x \paren {y - y_p}' + \map Q x \paren {y - y_p}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \paren {y + \map P x y' + \map Q x y} - \paren {y_p + \map P x y_p' + \map Q x y_p}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \map R x - \map R x\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 0\) |
We have that $\map {y_g} {x, C_1, C_2}$ is a general solution of $(2)$.
Thus:
- $\map y x - \map {y_p} x = \map {y_g} {x, C_1, C_2}$
or:
- $\map y x = \map {y_g} {x, C_1, C_2} + \map {y_p} x$
$\blacksquare$
Sources
- 1958: G.E.H. Reuter: Elementary Differential Equations & Operators ... (previous) ... (next): Chapter $1$: Linear Differential Equations with Constant Coefficients: $\S 2$. The second order equation: $\S 2.2$ The general equation
- 1972: George F. Simmons: Differential Equations ... (previous) ... (next): $\S 3.14$: Second Order Linear Equations: Introduction: Theorem $\text{B}$