Image of Element under Composite Relation

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Theorem

Let $\RR_1 \subseteq S_1 \times T_1$ and $\RR_2 \subseteq S_2 \times T_2$ be relations.

Let $\RR_2 \circ \RR_1 \subseteq S_1 \times T_2$ be the composition of $\RR_1$ and $\RR_2$.

Let $x \in S_1$.


Then:

$\RR_2 \sqbrk {\map {\RR_1} x \cap S_2} = \map {\paren{\RR_2 \circ \RR_1}} x$


Proof

We have:

\(\ds \RR_2 \sqbrk {\map {\RR_1} x \cap S_2}\) \(=\) \(\ds \RR_2 \sqbrk {\RR_1 \sqbrk {\set x} \cap S_2}\) Image of Singleton under Relation
\(\ds \) \(=\) \(\ds \paren{\RR_2 \circ \RR_1} \sqbrk {\set x}\) Image of Subset under Composite Relation
\(\ds \) \(=\) \(\ds \map {\paren{\RR_2 \circ \RR_1} } x\) Image of Singleton under Relation

$\blacksquare$

Also see