Primitive of Reciprocal of a squared minus x squared/Logarithm Form 1/size of x greater than a/Proof 2
< Primitive of Reciprocal of a squared minus x squared | Logarithm Form 1 | size of x greater than a
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Theorem
Let $\size x > a$.
Then:
- $\ds \int \frac {\d x} {a^2 - x^2} = \dfrac 1 {2 a} \map \ln {\dfrac {x + a} {x - a} } + C$
Proof
Let $\size x > a$.
Then:
\(\ds \int \frac {\d x} {a^2 - x^2}\) | \(=\) | \(\ds \int \frac {\d x} {\paren {a + x} \paren {a - x} }\) | Difference of Two Squares | |||||||||||
\(\ds \) | \(=\) | \(\ds \int \frac {\d x} {2 a \paren {a + x} } + \int \frac {\d x} {2 a \paren {a - x} }\) | Partial Fraction Expansion | |||||||||||
\(\ds \) | \(=\) | \(\ds \int \frac {\d x} {2 a \paren {x + a} } - \int \frac {\d x} {2 a \paren {x - a} }\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \frac 1 {2 a} \int \frac {\d x} {x + a} - \frac 1 {2 a} \int \frac {\d x} {x - a}\) | Primitive of Constant Multiple of Function | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac 1 {2 a} \ln \size {x + a} - \frac 1 {2 a} \ln \size {x - a} + C\) | Primitive of Reciprocal | |||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac 1 {2 a} \ln \size {\dfrac {x + a} {x - a} } + C\) | Difference of Logarithms |
If $x > a$, then both $x + a > 0$ and $x - a > 0$.
So $\dfrac {x + a} {x - a} > 0$ and so:
- $\ln \size {\dfrac {x + a} {x - a} } = \map \ln {\dfrac {x + a} {x - a} }$
If $x < -a$, then both $x + a < 0$ and $x - a < 0$.
So again $\dfrac {x + a} {x - a} > 0$ and so:
- $\ln \size {\dfrac {x + a} {x - a} } = \map \ln {\dfrac {x + a} {x - a} }$
Hence the result.
$\blacksquare$