Definition:Homomorphism (Abstract Algebra)

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Definition

Let $\phi: \left({S, \circ}\right) \to \left({T, *}\right)$ be a mapping from one algebraic structure $\left({S, \circ}\right)$ to another $\left({T, *}\right)$.

If $\circ$ has the morphism property under $\phi$, that is:

$\forall x, y \in S: \phi \left({x \circ y}\right) = \phi \left({x}\right) * \phi \left({y}\right)$

then $\phi$ is a homomorphism.


This can be generalised to algebraic structures with more than one operation:

Let:

  • $\left({S_1, \circ_1, \circ_2, \ldots, \circ_n}\right)$
  • $\left({T, *_1, *_2, \ldots, *_n}\right)$

be algebraic structures.


Let $\phi: \left({S_1, \circ_1, \circ_2, \ldots, \circ_n}\right) \to \left({T, *_1, *_2, \ldots, *_n}\right)$ be a mapping from $\left({S_1, \circ_1, \circ_2, \ldots, \circ_n}\right)$ to $\left({T, *_1, *_2, \ldots, *_n}\right)$.

If, $\forall k \in \left[{1 \,.\,.\, n}\right]$, $\circ_k$ has the morphism property under $\phi$, that is:

$\forall x, y \in S: \phi \left({x \circ_k y}\right) = \phi \left({x}\right) *_k \phi \left({y}\right)$

then $\phi$ is a homomorphism.


Semigroup Homomorphism

Let $\left({S, \circ}\right)$ and $\left({T, *}\right)$ be semigroups.

Let $\phi: S \to T$ be a mapping such that $\circ$ has the morphism property under $\phi$.


That is, $\forall a, b \in S$:

$\phi \left({a \circ b}\right) = \phi \left({a}\right) * \phi \left({b}\right)$


Then $\phi: \left({S, \circ}\right) \to \left({T, *}\right)$ is a semigroup homomorphism.


Group Homomorphism

Let $\left({G, \circ}\right)$ and $\left({H, *}\right)$ be groups.

Let $\phi: G \to H$ be a mapping such that $\circ$ has the morphism property under $\phi$.


That is, $\forall a, b \in R$:

$\phi \left({a \circ b}\right) = \phi \left({a}\right) * \phi \left({b}\right)$


Then $\phi: \left({G, \circ}\right) \to \left({H, *}\right)$ is a group homomorphism.


Ring Homomorphism

Let $\left({R, +, \circ}\right)$ and $\left({S, \oplus, *}\right)$ be rings.

Let $\phi: R \to S$ be a mapping such that both $+$ and $\circ$ have the morphism property under $\phi$.


That is, $\forall a, b \in R$:

\((1):\)      \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \phi \left({a + b}\right)\) \(=\) \(\displaystyle \phi \left({a}\right) \oplus \phi \left({b}\right)\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    
\((2):\)      \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \phi \left({a \circ b}\right)\) \(=\) \(\displaystyle \phi \left({a}\right) * \phi \left({b}\right)\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    


Then $\phi: \left({R, +, \circ}\right) \to \left({S, \oplus, *}\right)$ is a ring homomorphism.


Field Homomorphism

Let $\left({F, +, \times}\right)$ and $\left({K, \oplus, \otimes}\right)$ be fields.

Let $\phi: F \to K$ be a mapping such that both $+$ and $\times$ have the morphism property under $\phi$.


That is, $\forall a, b \in F$:

\((1):\)      \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \phi \left({a + b}\right)\) \(=\) \(\displaystyle \phi \left({a}\right) \oplus \phi \left({b}\right)\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    
\((2):\)      \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \phi \left({a \times b}\right)\) \(=\) \(\displaystyle \phi \left({a}\right) \otimes \phi \left({b}\right)\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    


Then $\phi: \left({F, +, \times}\right) \to \left({K, \oplus, \otimes}\right)$ is a field homomorphism.


F-Homomorphism

Let $R, S$ be rings with unity.

Let $F$ be a subfield of both $R$ and $S$.


Then a ring homomorphism $\varphi: R \to S$ is called an $F$-homomorphism if:

$\forall a \in F: \varphi \left({a}\right) = a$.

That is, $\varphi \restriction_F = I_F$ where:


R-Algebraic Structure Homomorphism

Let $\left({S, \ast_1, \ast_2, \ldots, \ast_n, \circ}\right)_R$ and $\left({T, \odot_1, \odot_2, \ldots, \odot_n, \otimes}\right)_R$ be $R$-algebraic structures.

Then $\phi$ is an $R$-algebraic structure homomorphism iff:

$(1): \quad \forall k: k \in \left[{1 .. n}\right]: \forall x, y \in S: \phi \left({x \ast_k y}\right) = \phi \left({x}\right) \odot_k \phi \left({y}\right)$
$(2): \quad \forall x \in S: \forall \lambda \in R: \phi \left({\lambda \circ x}\right) = \lambda \otimes \phi \left({x}\right)$


Note that this definition also applies to modules and vector spaces.


G-Module Homomorphism

Let $\left({G, \cdot}\right)$ be a group.

Let $\left({V, \phi}\right)$ and $\left({W, \mu}\right)$ be $G$-modules.


Then a linear mapping $f: V \to W$ is called a $G$-module homomorphism iff:

$\forall g \in G,\ \forall v \in V: f \left({\phi \left({g, v}\right)}\right) = \mu \left({g, f\left({v}\right)}\right)$


Image

As a homomorphism is a mapping, and therefore a relation, we define the image of a homomorphism in the same way:

$\operatorname{Im} \left({\phi}\right) = \left\{{t \in T: \exists s \in S: t = \phi \left({s}\right)}\right\}$


Homomorphism as Cartesian Product

Let $\phi: \left({S, \circ}\right) \to \left({T, *}\right)$ be a mapping from one algebraic structure $\left({S, \circ}\right)$ to another $\left({T, *}\right)$.

We define the cartesian product $\phi \times \phi: S \times S \to T \times T$ as:

$\forall \left({x, y}\right) \in S \times S: \left({\phi \times \phi}\right) \left({x, y}\right) = \left({\phi \left({x}\right), \phi \left({y}\right)}\right)$


Hence we can state that $\phi$ is a homomorphism iff:

$\ast \left({\left({\phi \times \phi}\right) \left({x, y}\right)}\right) = \phi \left({\circ \left({x, y}\right)}\right)$

using the notation $\circ \left({x, y}\right)$ to denote the operation $x \circ y$.


The point of doing this is so we can illustrate what is going on in a commutative diagram:

Homomorphism.png

Thus we see that $\phi$ is a homomorphism iff both of the composite mappings from $S \times S$ to $T$ have the same effect on all elements of $S \times S$.


Also see


Linguistic Note

The word homomorphism comes from the Greek morphe (μορφή) meaning form or structure, with the prefix homo- meaning similar.

Thus homomorphism means similar structure.


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