Kernel is Normal Subgroup of Domain
From ProofWiki
Theorem
Let $\phi$ be a group homomorphism.
Then the kernel of $\phi$ is a normal subgroup of the domain of $\phi$:
- $\ker \left({\phi}\right) \triangleleft \operatorname{Dom} \left({\phi}\right)$
Proof
Let $\phi: G_1 \to G_2$ be a group homomorphism, where the identities of $G_1$ and $G_2$ are $e_{G_1}$ and $e_{G_2}$ respectively.
By Kernel is Subgroup, $\ker \left({\phi}\right) \le \operatorname{Dom} \left({\phi}\right)$.
Let $k \in \ker \left({\phi}\right), x \in G_1$. Then:
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \phi \left({x k x^{-1} }\right)\) | \(=\) | \(\displaystyle \phi \left({x}\right) \phi \left({k}\right) \left({\phi \left({x}\right)}\right)^{-1}\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Homomorphism to Group Preserves Inverses | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \phi \left({x}\right) \left({\phi \left({x}\right)}\right)^{-1}\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | as $k \in \ker \left({\phi}\right)$ | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \phi \left({x}\right) \left({\phi \left({x}\right)}\right)^{-1}\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Property of Identity | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle e_{G_2}\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Property of Inverse |
So $x k x^{-1} \in \ker \left({\phi}\right)$.
As this is true for all $x \in G_1$, then from Normal Subgroup Equivalent Definitions, $\ker \left({\phi}\right)$ is a normal subgroup of $G_1$.
$\blacksquare$
Sources
- J.A. Green: Sets and Groups (1965)... (previous)... (next): $\S 7.4$
- Richard A. Dean: Elements of Abstract Algebra (1966): $\S 1.10$: Theorem $22$
- B. Hartley and T.O. Hawkes: Rings, Modules and Linear Algebra (1970): $\S 2.2$
- Allan Clark: Elements of Abstract Algebra (1971)... (previous)... (next): $\S 65$
- Thomas A. Whitelaw: An Introduction to Abstract Algebra (1978)... (previous)... (next): $\S 49.4$
- John F. Humphreys: A Course in Group Theory (1996): $\S 8$: Theorem $8.13$