Nowhere Dense iff Complement of Closure is Everywhere Dense/Warning
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Nowhere Dense iff Complement of Closure is Everywhere Dense: Warning
Note that in the result:
- $H$ is nowhere dense in $T$ if and only if the relative complement of its closure is everywhere dense in $T$
must be applied to the closure of $H$.
Otherwise, consider the real numbers $\R$ and the rational numbers $\Q$.
We have that:
- $\R \setminus \Q$ is the set of irrational numbers.
We have that Irrationals are Everywhere Dense in Reals.
But we also have from Rationals are Everywhere Dense in Reals:
- $\map \cl \Q = \R$
and so:
- $\paren {\map \cl \Q}^\circ = \R$
So it is not the case that $\R \setminus \Q$ is nowhere dense in $\R$.
However:
- $\R \setminus \map \cl \Q = \O$
which is indeed nowhere dense in $\R$.
Sources
- 1975: W.A. Sutherland: Introduction to Metric and Topological Spaces ... (previous) ... (next): $3$: Continuity generalized: topological spaces: $3.7$: Definitions: Example $3.7.30$